-108x^2+748x=0

Solution for -108x^2+748x=0 equation:

-108x^2+748x=0

a = -108; b = 748; c = 0;
Δ = b2-4ac
Δ = 7482-4·(-108)·0
Δ = 559504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{559504}=748$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(748)-748}{2*-108}=\frac{-1496}{-216}
=6+25/27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(748)+748}{2*-108}=\frac{0}{-216}
=0
$